Log2 15 x log 2 3. Log2 4. logg33 - logsl1 = log;3 = 1 b) 3-10g23 = log29 б) 108,167 = 8 г) 10232 - 10g22= log2 16-8.

$Log2 15 x log 2 3. Log2 4. logg33 - logsl1 = log;3 = 1 b) 3-10g23 = log29 б) 108,167 = 8 г) 10232 - 10g22= log2 16-8.$